Usain is walking for exercise by zigzagging across a 100-meter by 30-meter rectangular field, beginning at point A and ending on the segment BC. He wants to increase the distance walked by zigzagging as shown in the figure below (APQRS). What angle θ ∠PAB=∠QPC=∠RQB=⋯ will produce a length that is 120 meters? (This figure is not drawn to scale. Do not assume that the zigzag path has exactly four segments as shown; there could be more or fewer.) [asy] import olympiad; draw((-50,15)--(50,15)); draw((50,15)--(50,-15)); draw((50,-15)--(-50,-15)); draw((-50,-15)--(-50,15)); draw((-50,-15)--(-22.5,15)); draw((-22.5,15)--(5,-15)); draw((5,-15)--(32.5,15)); draw((32.5,15)--(50,-4.090909090909)); label("θ", (-41.5,-10.5)); label("θ", (-13,10.5)); label("θ", (15.5,-10.5)); label("θ", (43,10.5)); dot((-50,15)); dot((-50,-15)); dot((50,15)); dot((50,-15)); dot((50,-4.0909090909)); label("D",(-58,15)); label("A",(-58,-15)); label("C",(58,15)); label("B",(58,-15)); label("S",(58,-4.0909090909)); dot((-22.5,15)); dot((5,-15)); dot((32.5,15)); label("P",(-22.5,23)); label("Q",(5,-23)); label("R",(32.5,23)); [/asy] $\textbf{( )
(A) }~\arccos\frac{5}{6}\qquad\textbf{
(B) }~\arccos\frac{4}{5}\qquad\textbf{
(C) }~\arccos\frac{3}{10}\qquad\textbf{
(D) }~\arcsin\frac{4}{5}\qquad\textbf{
(E) }~\arcsin\frac{5}{6}$